How to pass the Directory path as command line for the process??

Question

Hi

iam using regasm.exe to generate tlb file and register the assembly programatically.But the path of tlb in .NET root directory itself. so do like this

buffer contains c:\windows\Microsoft.Net\framework\v2.0.57\RegAsm.exe

if(!CreateProcessW(buffer,L" C:\Program Files\Test\Test.dll /codebase /tlb /silent" ,NULL, NULL,FALSE, 0,NULL,NULL,(LPSTARTUPINFOW)&si,&pi ) )

But i think it wont tkae fulpath since there is a blank b/w Program and Files.as expected the when i run the command it also shows unable to locate input assembly c:\program.

normally at coomand prompt we can give as

RegAsm.exe "c:\program files\Test\test.dll" /codebase /tlb this bold characters i have to pass as command line but it have Double quptes with in double quotes. so i was strucked.

How can i fix it

Answer 1

Just see the documentation for the CreateProcess Function: http://msdn.microsoft.com/en-us/library/ms682425%28VS.85%29.aspx

It says:

lpCommandLine [in, out, optional] The Unicode version of this function, CreateProcessW, can modify the contents of this string. Therefore, this parameter cannot be a pointer to read-only memory (such as a const variable or a literal string). If this parameter is a constant string, the function may cause an access violation.

It has an example where one specifies an executable in "Program Files" Directory. . I am not that good in C++. Else would have given an example.

Answer 2

You need to enclose the path in quotes within the string, which you can do by escaping the quote character by preceding it with a backslash. So, your 2nd parameter to CreateProcessW would be:

L"\"C:\Program Files\Test\Test.dll\" /codebase /tlb /silent"

This would give you the command line with quotes that you would use at the command prompt.