How to extract the text between <a></a>

Question

I must use jQuery for first time....

<a class="Tag Resource" href="http://localhost/" 
resource="http://localres/" property="prop">test</a>

I've tried to extract the text using var = $('a').find('Tag Resource').text(); and var = $('a').find('Tag Resource').html(); but it doesn't work. I need "test" as plain text.

Can someone tell me how to do this?

Thanks in advance

Answer 1

I think you're looking for:

var t = $("a.Tag.Resource").text();

meaning a tags that have both the Tag and Resource classes. The find() method is for searching subtrees of elements.

Answer 2

I think the problem is the syntax of your find expression.

Update: In fact, you don't want find at all, you want filter. Find will only select descendants of the a elements, rather than the elements themselves.

I've tested the example line below.

From the example here, it looks like you want

var text = $('a').filter('.Tag.Resource').text();

Answer 3

var text = "";
$("a").each(function(){
  text += $(this).html() + " " + $(this).attr("resource");
});
alert(text);

Answer 4

Here you go (live demo):

$(document).ready(
  function (){ 
    alert(  $('a.Tag.Resource').html()  );  
});

Your issue is either that you wanted one class but used a space so it became two; or that when referring to classes with a jquery selector, you need to prefix them with a period.

In any case, the above code will help. If you really just wanted one class, change it to $('a.Tag-Resource')...

Answer 5

I don't think you can have class names with spaces in. You've added 2 classes "Tag" and"Resource" to the a tag and your find selectory won't find that.

Answer 6

Remember, class names can be repeated on a page, and spaces indicate two classes applied to an element. You are not guaranteed that a single element will have that class, so .text() may return the combined text of all matched elements.

$(".Tag.Resource").text();

Answer 7

Well, you don't have to use JQuery...

var text, links = document.links;
for (var i = 0; i < links.length; i++) {
   if (links[i].className == 'Tag Resource') {
      text = links[i].innerText;
      break;
   }
}
alert(text);