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Answer 1

A:

How is the NSString returned by valueForKey: formed? Is it something like "image.png", or is it "/image.png"? If it's the former, you'll want to use stringByAppendingPathComponent: instead of stringByAppendingString:.

Cinder6 2009-08-18 05:29:20

Thanks for your response...the URL formed from this code is correct and displays the image when input into a browser...

2009-08-19 03:44:17

What's the URL string look like after the string has been concatenated?

Cinder6 2009-08-19 16:45:52

it's fully formed and resolves correctly in a browser:http://localhost:3000/pictures/picture.jpg

2009-08-20 02:39:44

So it it `@"localhost:3000..."`, or is it `@"http://localhost:3000..."`? Your initial question says the latter, but make sure, because NSURL won't work without the http://. Another thing you could test is to see if it's storing the port correctly--try the `port` method, which returns an `NSNumber`.

Cinder6 2009-08-20 02:55:53

My comment should have had http:// on the latter string--forgot to escape the URL.

Cinder6 2009-08-20 02:56:30

Thanks for the quick response.My apologies, the localhost URL should have http:// in front of it..really what I am doing is hardcoding "http://localhost:3000" and then appending a string retrieved from an XML page ("/pictures/picture.jpg") and passing the resulting string to NSURL....the concatenated string WORKS if i just pass it directly in to NSURL (=source of confusion).

2009-08-20 03:06:49

Subview Controller's viewdidload method:- (void)viewDidLoad { [super viewDidLoad]; imageView = [[UIImageView alloc] init]; NSString * imagePath = @"http://localhost:3000"; NSString * specificPath = (NSString *)[item valueForKey:@"picture"] ; NSString * url = [imagePath stringByAppendingString:specificPath]; NSLog(@"url = "); NSLog(url); //prints correct URL NSData* imageData = [[NSData alloc]initWithContentsOfURL:[NSURL URLWithString:url]]; UIImage* image = [[UIImage alloc] initWithData:imageData]; [imageView setImage:image]; [imageData release]; [image release];}

2009-08-20 03:16:08

Try comparing the concatenated string with the hardcoded version (isEqualToString:), just to make sure they are exactly the same. Also make sure the port is getting set properly in the NSURL object (port method).

Cinder6 2009-08-20 03:18:39

weird! the two strings are not equal!how do i fix this!?

2009-08-20 04:18:05

hmm turns out there were some whitespace characters that came back from the XML string. I have them removed and the strings are equal but i am getting the same result.Also: NSString * port = [[nsurl port] stringValue]; NSLog(@"urlport"); NSLog(port);is not printing anything

2009-08-20 04:55:47

Strange. Is the encoding for the concatenated string something different from UTF8? Also, for easier NSLog use, you can do something like NSLog(@"%@", [url port]); It's just like printf.

Cinder6 2009-08-20 05:12:16

Answer 2

A:

Hi.

You need to use the UIWebView and load a html <img /> inside it. At least this is a nice workaround.

Check the code here http://blog.timeister.com/2009/07/18/iphone-show-online-image/

- (void)loadImage:(NSString*)url frame:(CGRect)frame {
NSString* textHTML = @"
<html><head>
<style type=\"text/css\">
body {
background-color: transparent;
color: white;
}
</style>
</head><body style=\"margin:0\">
<img  src=\"%@\"  width=\"%0.0f\" height=\"%0.0f\"></img>
</body></html>";

NSString* html = [NSString stringWithFormat:textHTML, url, frame.size.width, frame.size.height];

if(webView == nil) {
webView = [[UIWebView alloc] initWithFrame:frame];
[self.view addSubview:webView];
}

[webView loadHTMLString:html baseURL:nil];
}

Adrian

Adrian Pirvulescu 2009-08-18 05:45:06

I will try this.I am confused though because when I simply use the image's full URL directly in the [NSURL URLWithString] method, the image appears...

2009-08-19 03:45:06

The fact it works with a hard-coded URL tells you the problem lies in the string creation. I think you'll get the same result with this solution--you need to make sure the NSURL object created with the concatenated string isn't null.

Cinder6 2009-08-20 04:08:57

Answer 3

A:

I think problem is related to proper encoding.

try encoding the parameters properly by using following function :

encodedparams = [params stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];

So in your case :

NSString * specificPath = (NSString *)[item valueForKey:@"pictureLocation"] ;
specificPath = [specificPath stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];

I think this will solve your problem.

Gaurav Verma 2010-01-27 06:13:30

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