Access base class fn with same signature from derived class object

Question

Hi,

Is it possible to access a base class function which has the same signature as that of a derived class function using a derived class object?. here's a sample of what I'm stating below..

class base1 {
public:
    void test()
    {cout<<"base1"<<endl;};
};

class der1 : public base1 {
public:
    void test()
    {cout<<"der1"<<endl;};
};

int main() {
der1 obj;
obj.test(); // How can I access the base class 'test()' here??
return 0;
}

Answer 1

You need to fully qualify the method name as it conflicts with the inherited one.

Use obj.base1::test()