Reverse in Oracle this path z/y/x to x/y/z

Question

How would I do in a SELECT query to reverse this path :

z/y/x

for

x/y/z

where / is the delimiter and where there can be many delimiters in a single line

ex: select (... z/y/x/w/v/u ...) reversed_path from ...

Answer 1

Are you looking for REVERSE?
i.e

SELECT REVERSE('z/y/x') FROM DUAL;

Answer 2

The simplest way would probably be to write a stored pl/sql function, however it can be done with SQL (Oracle) alone.

This will decompose the path in subpath:

SQL> variable path varchar2(4000);
SQL> exec :path := 'a/b/c/def';

PL/SQL procedure successfully completed
SQL> SELECT regexp_substr(:path, '[^/]+', 1, ROWNUM) sub_path, ROWNUM rk
  2    FROM dual
  3  CONNECT BY LEVEL <= length(regexp_replace(:path, '[^/]', '')) + 1;

SUB_P RK
----- --
a      1
b      2
c      3
def    4

We then recompose the reversed path with the sys_connect_by_path:

SQL> SELECT MAX(sys_connect_by_path(sub_path, '/')) reversed_path
  2    FROM (SELECT regexp_substr(:path, '[^/]+', 1, ROWNUM) sub_path,
  3                 ROWNUM rk
  4             FROM dual
  5           CONNECT BY LEVEL <= length(regexp_replace(:path, '[^/]', '')) + 1)
  6  CONNECT BY PRIOR rk = rk + 1
  7   START WITH rk = length(regexp_replace(:path, '[^/]', '')) + 1;

REVERSED_PATH
-------------
/def/c/b/a