NSDateFormatter, am I doing something wrong or is this a bug?

Question

I'm trying to print out the date in a certain format:

NSDate *today = [[NSDate alloc] init];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyyMMddHHmmss"];
NSString *dateStr = [dateFormatter stringFromDate:today];

If the iPhone is set to 24 hour time, this works fine, if on the other hand the user has set it to 24 hour time, then back to AM/PM (it works fine until you toggle this setting) then it appends the AM/PM on the end even though I didn't ask for it:

20080927030337 PM

Am I doing something wrong or is this a bug with firmware 2.1?

Edit 1: Made description clearer

Edit 2 workaround: It turns out this is a bug, to fix it I set the AM and PM characters to "":

[dateFormatter setAMSymbol:@""];
[dateFormatter setPMSymbol:@""];

Answer 1

Using the code you posted on both the simulator and a phone with the 2.1 firmware and 24-hour time set to off, I never had an AM/PM appended to dateStr when I do:

NSLog(@"%@", dateStr);

Are you doing anything else with dateStr that you didn't post here? How are you checking the value?

Follow up

try turning the am/pm setting on then off. I didn't have the problem either, until I did that. I am printing it out the same way you are.

Okay, I see it when I do this also. It's gotta be a bug. I recommend you file a bug report and just check for and filter out the unwanted characters in the meantime.

Answer 2

I'm having this problem as well. However the workaround to set AM/PM symbols to @"" doesn't solve the problem - if the time is 6:00 PM, it will just show up as 6:00, not 18:00.

Answer 3

Here's the explanation of the iPhone SDK bug (also still there in 3.1 beta SDK)

First, a little background on the iPhone user interface. When iPhone users change their region format between, say, “United States” and “France”, the users’ “24-Hour Time” setting is automatically switched to the mode that is most prevalent in that region. In France, that would set 24-Hour Time to “ON”, and in the U.S., that would set it to “OFF”. The users can then manually override that setting and that’s where trouble starts.

The problem comes from NSDateFormatter somehow “getting stuck” in the 12 or 24-hour time mode that the user has manually selected. So if a French user manually selects 12-hour mode, and the application requested NSDateFormatter to output time with the 24-hour format “HHmm”, it would actually receive time in a 12-hour format, e.g. “01:00 PM”, as if the application had instead requested “hhmm aa”. The reverse would happen if a US user manually selected 24-hour mode: outputting time with the 12-hour format “hhmm aa” would actually get you time in the 24-hour format instead, e.g. “17:00″.

More details and a possible workaround can be found on this blog.

Answer 4

For those finding this question who want to use NSDateFormatter to parse 24-hour time and are hitting this bug, using NSDateComponents to parse dates and times which have a known format sidesteps this issue:

NSString *dateStr = @"2010-07-05";
NSString *timeStr = @"13:30";

NSDateComponents *components = [[NSDateComponents alloc] init];
components.year = [[dateStr substringToIndex:4] intValue];
components.month = [[dateStr substringWithRange:NSMakeRange(5, 2)] intValue];
components.day = [[dateStr substringFromIndex:8] intValue];
components.hour = [[timeStr substringToIndex:2] intValue];
components.minute = [[timeStr substringFromIndex:3] intValue];

NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

NSDate *date = [calendar dateFromComponents:components];

[components release];
[calendar release];

Answer 5

I think this is the solution .

NSDateFormatter *df =[[NSDateFormatter alloc] init]; [df setDateFormat:@"yyyy-MM-dd HH:mm:ss"]; NSLocale *usLocale = [[NSLocale alloc] initWithLocaleIdentifier:@"en_US"];

[df setLocale: usLocale];

[usLocale release];

NSDate *documento_en_Linea =[[[NSDate alloc] init]autorelease];

documento_en_Linea=[df dateFromString:@"2010-07-16 21:40:33"];

[df release];

    NSLog(@"fdocumentoenLineaUTC:%@!",documento_en_Linea);

//ouput
fdocumentoenLineaUTC:2010-07-16 09:40:33 p.m. -0500!

Answer 6

this should also work (i am seeing some bizzare results tho)

-(NSString*)lowLevTime:(NSString*)stringFormat {
    char buffer[50];
    const char *format = [stringFormat UTF8String];
    time_t rawtime;
    struct tm * timeinfo;
    time(&rawtime);
    timeinfo = localtime(&rawtime);
    strftime(buffer, sizeof(buffer), format, timeinfo);
    return [NSString  stringWithCString:buffer encoding:NSASCIIStringEncoding];
}

Answer 7

thanks i have searched all the internet...it helped me a lot....