Hello!
My problem would be that I make a POST request with jqurery, and if there is an error I modify the HTTP status to for example 401 and echo the error. (I'm using $.ajax();) So, the problem is that I don't know how to print out that error message.
If I check it in firebug I get something like this: {"*THE URL OF THE FILE*":{"rc":401,"body":"*error message*"}}
Can anybody tell me that how to print that error message out? (For example with alert();)
Thanks.