Struct initialization of the C/C++ programming language?

Question

I could do struct initialization with code:

struct struct_type_id struct_name_id = { value1, value2, value3 };

but could not with:

struct struct_type_id struct_name_id;
struct_name_id = { value1, value2, value3 };

why I could do it with the former,but could not with the latter with gcc,g++,vc2008,vc6?In other words,why the c/c++ programming language do not support this syntax?

thanks.

Answer 1

You just need to cast the values as such:

struct_name_id = (struct struct_type_id){ value1, value2, value3 };

Answer 2

The first statement creates a variable initialized to the given values, i.e., these values are built in memory and stored directly in the program executable in that variable address (for globals) or ready for memory copy (for stack variables).

The second statement of the second block is very different. Although it looks similar, it is an assign expression. It means that the RHS of the equals operator is an expression that is evaluated (independently of what is in the LHS of =), and then passed to the = operator. Without proper context, {...} doesn't have any meaning.

In C99, you can do this:

struct_name_id = (struct struct_type_id){ value1, value2, value3 };

Now the RHS of the equals operator is a valid expression, since there is proper context for the compiler to know what is in {...}.

In C++0x, the syntax is:

struct_name_id = struct_type_id({ value1, value2, value3 });

Answer 3

I don't know why C didn't originally support some kind of syntax to 'reinitialize' a struct using something like the initializer list - there are definitely times when I would have found it handy. As Juliano mentioned, C99 (and C++0x) has fixed it to a certain degree, but I often have to stick with C90. When I want to do something like that, I'll sometimes do the following:

struct foo const init_foo = { 1, 2, 3};
struct foo myFoo;

// ....

myFoo = init_foo;  // reinitialize myFoo

Answer 4

Will this work for you ?

typedef struct name_id {int value1; int value2; int value3;} NAME_ID;
name_id mynameid = {0,1,2};

Answer 5

I faced a similar problem, and the solution to that was that I was trying to initialized the struct outside the function(not using the initializer syntax, but with the obj.member = VALUE; notation). It is a related problem, so posting here, hoping someone with the same question lands up here.