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389

answers:

4

I have 4 elements:List[List[Object]] (Objects are different in each element) that I want to zip so that I can have a List[List[obj1],List[obj2],List[obj3],List[obj4]]

I tried to zip them and I obtained a nested list that I can't apply flatten to because it says: no implicit argument matching parameter type.

How can I solve this? should I try another way or is there any way to make the flatten work?

I'm kinda new to scala so it may be a dumb question :D Thanks in advance! clau

A: 

It helps if we have an example. Your code should look something like:

val f = List(1, 2)
val s = List(3, 4)
val top = List(f, s)

List.flatten(top) // returns List(1, 2, 3, 4)
Shaun
+2  A: 

From the error you pasted, it looks like you're trying to call the flatten instance method of the nested list itself. That requires an implicit conversion to make something of type Iterable out of whatever types the List contains. In your case, it looks like the compiler can't find one.

Use flatten from the List singleton object, which doesn't require that implicit parameter:

scala> val foo = List(List(1), List("a"), List(2.3))
foo: List[List[Any]] = List(List(1), List(a), List(2.3))

scala> List.flatten(foo)
res1: List[Any] = List(1, a, 2.3)
Ben James
A: 

You can only zip two lists at a time with list1 zip list2, and the type signature for the return values is List[(A,B)] not List[List[obj1],List[obj2],List[obj3],List[obj4]]

Ken Bloom
+2  A: 

The question is very vague. You should plain paste what you have, instead of trying to describe it. It would make everyone's (including your's) life much easier.

The code below is one example based on an assumption of what you have.

scala> List(List(1))
res0: List[List[Int]] = List(List(1))

scala> List(List(2))
res1: List[List[Int]] = List(List(2))

scala> List(List(3))
res2: List[List[Int]] = List(List(3))

scala> List(List(4))
res3: List[List[Int]] = List(List(4))

scala> res0 ::: res1 ::: res2 ::: res3
res4: List[List[Int]] = List(List(1), List(2), List(3), List(4))
Daniel