I can't seem to find an easy way to do it. The exact thing I need is:
[NSString stringWithFormat:@"%d doodads", n];
Where n is an int. So for 1234 I'd want this string (under my locale):
@"1,234 doodads"
Thanks.
views:
227answers:
3So the absolute easiest way to do this is `[NSString stringWithFormat:@"%d doodads", [[[NSNumberFormatter alloc] autorelease] stringFromNumber:n]]];`? As that is more verbose than I hoped.
Max Howell
2009-11-17 21:34:04
Max Howell: Normally, you would hold on to the number formatter in an instance variable (which you can make an outlet to keep the formatter in a nib), which makes the expression simply `[myFormatter stringFromNumber:[NSNumber numberWithInt:n]]`. (Also, you generally should use `NSInteger` and `numberWithInteger:`, not `int` and `numberWithInt:`, to take advantage of greater range on 64-bit machines.)
Peter Hosey
2009-11-17 21:43:05
I can't get this to work. Even using setHasThousandSeparators:YES changes nothing — no thousand separators.
Max Howell
2009-11-18 00:52:22
A:
This was the only way I could make it work.
NSNumberFormatter* formatter = [[NSNumberFormatter alloc] init];
[formatter setFormatterBehavior:NSNumberFormatterBehavior10_4];
[formatter setFormat: @"#,###"];
NSString* doodads = [formatter stringFromNumber:[NSNumber numberWithInt:n]];
[formatter release];
The docs aren't clear if this is properly localised or not. I'm guessing no, it isn't, it will always use commas. Which sucks.
Max Howell
2009-11-18 01:14:27
A:
For 10.6 this works:
numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setFormatterBehavior: NSNumberFormatterBehavior10_4];
[numberFormatter setNumberStyle: NSNumberFormatterDecimalStyle];
NSString *numberString = [numberFormatter stringFromNumber: [NSNumber numberWithInteger: i]];
And it properly handles localization.
Todd Ransom
2010-10-16 14:02:02