ansaurus

Question

Answer 1

+1 A:

The exit code is stored in the ERRORLEVEL environment variable:

echo %ERRORLEVEL%

To test it you can create a simple batch file that exits using the exit code passed as parameter:

exit_code.bat

@exit /b %1

Testing:

> exit_code.bat 8
> echo %ERRORLEVEL%
8

Kaniabi 2009-11-20 14:31:57

my command line is always returning 9009 error code. Do you know why?

Lastnico 2009-11-20 14:45:07

This doesn't seem to work for me.

Scott 2009-11-20 18:11:49

It's just a typo in his code, it's supposed to be %1 instead of %i, no reason to downvote.

JRL 2009-11-20 18:31:10

I can't un-downvote until the answer is edited. Kaniabi, if you edit your answer to correct, I should be able to un-downvote. Thanks!

Scott 2009-11-20 18:42:00

Ops. Typo fixed.Thanks all for the feedback.

Kaniabi 2009-11-25 11:37:39

Lastnico: Strange return code. I tried to execute with the typo and it always returns 0, not 9009.

Kaniabi 2009-11-25 11:39:42

Answer 2

+2 A:

Lastnico,

Hello, I think I have a solution to your problem. Try the following:

Try this at your command prompt:

C:\> cmd /c exit /b 4

C:\> echo %errorlevel%

The result should be 4.

Here is a screen shot of my result:

Result of Code

I hope this helps,

Thanks!

Scott 2009-11-20 18:16:51

Perfect! Thank you.

Lastnico 2009-11-23 13:31:39