Can I construct an std::map
where the key type is a reference type, e.g. Foo &
and if not, why not?
views:
315answers:
4
+2
A:
No, because many of the functions in std::map takes a reference to the keytype and references to references are illegal in C++.
/A.B.
Andreas Brinck
2009-11-25 10:49:04
+1
A:
Consider the operator[](const key_type & key)
.
If key_type
is Foo &
then what is const key_type &
?
The thing is that it does not work. You can not construct an std::map where the key type is a reference type.
Alexey Malistov
2009-11-25 10:49:28
+8
A:
According to C++ Standard 23.1.2/7 key_type
should be assignable. Reference type is not.
Kirill V. Lyadvinsky
2009-11-25 10:54:47
+1
A:
Pointer as a key-type for std::map is perfectly legal
#include <iostream>
#include <cstdlib>
#include <map>
using namespace std;
int main()
{
int a = 2;
int b = 3;
int * c = &a;
int * d = &b;
map<int *, int> M;
M[c]=356;
M[d]=78;
return 0;
}
Initialised references cant be keys:
#include <iostream>
#include <cstdlib>
#include <map>
using namespace std;
int main()
{
int a = 2;
int b = 3;
int & c = a;
int & d = b;
map<int &, int> M;
M[c]=356;
M[d]=78;
return 0;
}
In file included from /usr/include/c++/4.4/map:60,
from test.cpp:3:
/usr/include/c++/4.4/bits/stl_tree.h: In instantiation of 'std::_Rb_tree<int&, std::pair<int&, int>, std::_Select1st<std::pair<int&, int> >, std::less<int&>, std::allocator<std::pair<int&, int> > >':
/usr/include/c++/4.4/bits/stl_map.h:128: instantiated from 'std::map<int&, int, std::less<int&>, std::allocator<std::pair<int&, int> > >'
test.cpp:14: instantiated from here
/usr/include/c++/4.4/bits/stl_tree.h:1407: error: forming pointer to reference type 'int&
'
Nadir SOUALEM
2009-11-25 11:17:05
Keep in mind that ordering based on pointers is non-deterministic and likely to change with each invocation of the program.
Rob K
2009-11-25 15:16:40
michalmocny
2010-10-23 05:29:53