How to raise a double value by power of 12?

Question

I have a double which is:

double mydouble = 10;

and I want 10^12, so 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10. I tried

double newDouble = pow(10, 12);

and it returns me in NSLog: pow=-1.991886

makes not much sense... I think pow isn't my friend right?

Answer 1

try pow(10.0, 12.0). Better yet, #include math.h.

To clarify: If you don't include math.h, the compiler assumes that pow() returns an integer. Including math.h brings in a prototype like

double pow(double, double);

So the compiler can understand how to treat the arguments and the return value.

Answer 2

That's the right syntax for pow, what format string are you passing to NSLog(…)?

Answer 3

did you try casting to a double:

NSLog(@"(double)pow(10, 12)                    = %lf", (double)pow(10, 12));

Answer 4

I couldn't even get the program to compile without:

#include <math.h>

When using math functions like this you should ALWAYS include math.h and make sure you are calling the right pow function. Who knows what the other pow function might be ... it could stand for "power wheels" haha

Answer 5

Here's how to compute x^12 with the fewest number of multiplications.

y = x*x*x; y *= y; y *= y;

The method comes from Knuth's Seminumerical Algorithms, section 4.6.3.