There will not be any ClassCastException, except when your T has some base:
public class GenericsTest
{
public static void main(String[] args)
{
System.out.println(cast(Integer.valueOf(0)));
System.out.println(GenericsTest.<Long> cast(Integer.valueOf(0)));
System.out.println(GenericsTest.<Long> cast("Hallo"));
System.out.println(castBaseNumber(Integer.valueOf(0)));
System.out.println(GenericsTest.<Long> castBaseNumber(Integer.valueOf(0)));
System.out.println(GenericsTest.<Long> castBaseNumber("Hallo"));
}
private static <T extends Number> T castBaseNumber(Object o)
{
T t = (T)o;
return t;
}
private static <T> T cast(Object o)
{
T t = (T)o;
return t;
}
}
In the above example, there will be no ClassCastException in the first 5 calls to cast and castBaseNumber. Only the 6th call throws a ClassCastException, because the compiler effectively translates the cast() to return (Object) o and the castBaseNumber() to return (Number)o;. Wenn you write
String s = GenericsTest.<Long> cast("Hallo");
You would get a ClassCastException, but not whithin the cast-method, but at the assignment to s.
Therefore I do think, your "T" is not just "T", but "T extends Something". So you could check:
Object o = decoder.readObject();
if (o instanceof Something)
restoredItem = (T) o;
else
// Error handling
But this will still lead to an error later, when the you use your class.
public Reader<T extends Number>{...}
Long l = new Reader<Long>("file.xml").getValue(); // there might be the ClassCastException
For this case only Tom's advise might help.