Based on other my question.
Consider the following code
template<typename T, int N>
struct A {
typedef T value_type; // save T to value_type
static const int size = N; // save N to size
};
Look, I can use value_type
and size
as template parameter.
typedef A<int, 2> A1;
typedef A<A1::value_type, A1::size + 3> A2; // OK, A2 is A<int,5>
Now I want to do the same with pointer to member:
struct Foo {
int m;
int r;
};
template<int Foo::*Mem>
struct B {
static int Foo::* const mp;
};
template<int Foo::*Mem>
int Foo::* const B<Mem>::mp = Mem; // Save pointer to member
But I get error.
typedef B<&Foo::m> B1;
typedef B<B1::mp> B2; // DOES NOT WORK
How to make last line to work? Or how to get similiary result?
Note. I know that it does not work. No links to C++ Standard is needed. I need workaround.