This MSDN page mentions that there're nothrow versions of new
and delete
. nothrow new
is quite a known thing - returns null instead of throwing an exception if memory allocation fails. But what is nothrow delete
mentioned there?
views:
285answers:
1They are probably referring to the raw memory allocation functions operator new
and operator delete
.
When you invoke a specific version of placement new-expression (i.e. new-expression with extra parameters; they all are officially referred to as placement forms of new
) and the memory allocation function operator new
succeeds, but the process fails later for some other reason (the constructor throws), the implementation has to abort the process and automatically release the allocated memory by calling the appropriate version of operator delete
. "Appropriate version" of operator delete
in this case is the version that has the same set of parameters as the operator new
function previously used for memory allocation (except for the very first parameter, of course).
This applies to nothrow
version of operator new
as well. When you use a nothrow
form of new-expression, it calls a nothrow
version of operator new
and then constructs the object in the allocated memory. If the constructor fails (throws), the implementation of the new-expression releases allocated memory with the help of nothrow
version of operator delete
. This is basically the only reason for this version of operator delete
to exist.
In other words, the nothrow
version of operator delete
exists for very specific internal purposes. You should not normally want to call it yourself and, maybe, you don't really need to know about its existence. However, it is worth knowing that for the reasons described above, whenever you create your own version of operator new
with extra parameters, it is always a good idea to provide a matching version of operator delete
with the same set of extra parameters.