Unsticky a cout modifier?

Question

  cout << hex << 11 << endl;
  cout << 12 << endl;

will print :

a

b

If I cout 13, it will be printed as 'c'. How do I remove the hex modifier from now on so it would just print 13? This is probably simple but I tried looking for the answer elsewhere. Thanks.

Answer 1

cout << dec

Also look here

Answer 2

using namespace std;
cout<<hex<<11<<endl;
cout<<dec<<12<<endl;
cout<<13<<endl;

Answer 3

write in your code

cout << dec << 13

Answer 4

You might want to look at the Boost iostream state saver library. This makes it fairly easy to save a state, set a new state, then restore the original (saved) state.