Maximum value of long number?

Question

I'm trying to declare a long value in Java, which unfortunately does not work.

This is my code. It results in the following error message: "The literal 4294967296 of type int is out of range".

long bytes = 4294967296;

I need this value to make a file filter that filters out files that are bigger than 4294967296 bytes (4GB). The other way round works without any issues (long size = file.length()) with every file size, which is why I can't figure out why my declaration is not working.

Answer 1

try long bytes = 4294967296L; to indicate to the compiler that you are using a long.

Answer 2

Add L to the end of the number:

long bytes = 4294967296L;

Answer 3

Soufiane is correct. Here is a doc that shows how to declare literals of the various types of numbers in Java:

http://www.janeg.ca/scjp/lang/literals.html

Answer 4

long literals are followed by the letter L or l (see: JLS 3.10.1). Uppercase is better because it's more legible, lowercase l looks too similar to 1.

For your particular number, it's probably easier to write:

 long bytes = (1L << 32);

This way, someone who reads the code can quickly tell that bytes is exactly 2 to the power of 32.

Answer 5

To answer your question title, the maximum value of a long can be obtained via the constant:

Long.MAX_VALUE

To solve your problem - add the l (L) literal after the number.