inheriting a class from a partial specialization of a template class

Question

I have a templated class named check and its partial specialization, now i am publically inheriting a class named childcheck from the partial specialization of the class check. but compiler gives following error message
no matching function for call to `check::check()'
candidates are: check::check(const check&)
check::check(t*) [with t = int*]
look at the code and explain the reason please

#include<iostream.h>
template<class t>
class check
{
t object;
public:
check(t);
};
//defining the constructor
template<class t>
check<t>::check<t>(t element)
{
cout<<"general templated class constructor"<<endl;
}



//partial specialization
template<class t>
class check<t*>
{
t* object;
public:
check(t*);
};
template<class t>
check<t*>::check<t*>(t* element)
{
cout<<"partial specialization constructor"<<endl;
}



//childcheck class which is derived from the partial specialization
template<class t>
class childcheck:public check<t*>//inheriting from the partial specialization
{
t object;
public:
childcheck(t);
};
template<class t>
childcheck<t>::childcheck<t>(t element):check<t>(element)
{
cout<<"child class constructor"<<endl;
}



main()
{
int x=2;
int*ptr=&x;
childcheck<int*>object(ptr);
cout<<endl;
system("pause");
}

Answer 1

You inherit from check<t*> yet call a base class constructor check<t> as if you inherited from check<t>. Which check<> do you want to inherit from?

I believe that what you really want do is this:

template<class t> 
class childcheck:public check<t>

If t is int*, then childcheck<int*> will inherit from check<int*> which is fine. The rest of your code can remain the way it is in the original question.

Read about Template Partial Specialization at cprogramming.com, it explains your previous question.