How do I use a manipulator to fomat my hex output with padded left zeros

Question

The little test program below prints out:

And SS Number IS =3039

I would like the number to print out with padded left zeros such that the total length is 8. So:

And SS Number IS =00003039 (notice the extra zeros left padded)

And I would like to know how to do this using manipulators and a stringstream as shown below. Thanks!

The test program:

#include <iostream>
#include <sstream>
#include <string>
#include <vector>

int main()
{

    int i = 12345;
    std::stringstream lTransport;

    lTransport << "And SS Number IS =" << std::hex << i << '\n';

    std::cout << lTransport.str();

}

Answer 1

Have you looked at the library's setfill and setw manipulators?

#include <iomanip>
...
lTransport << "And SS Number IS =" << std::hex << std::setw(8) ;
lTransport << std::setfill('0') << i << '\n';

The output I get is:

And SS Number IS =00003039

Answer 2

I would use:

cout << std::hex << std::setw(sizeof(i)*2) << std::setfill('0') << i << std::endl;

Answer 3

You can use setw and setfill functions as follows:

#include <iostream>
#include <sstream>
#include <string>
#include <vector>
#include <iomanip>

using namespace std;

int main()
{    
    int i = 12345;
    std::stringstream lTransport;

    lTransport << "And SS Number IS =" << setfill ('0') << setw (8)<< std::hex << i << '\n';    
    std::cout << lTransport.str();  // prints And SS Number IS =00003039    
}