Fastest/One-liner way to conditionally remove multiple directories on Unix

Question

What is the shortest way I can write:

rm -rfv public/stylesheets public/images public/javascripts

and make it conditional, with something like:

if [ ! -d public/stylesheets ]; then rm -rfv public/stylesheets; fi ...

Just discovered/found a use for command-line conditionals :)

Answer 1

for i in public/{stylesheet,image,javascript}s; do [ -d $i ] || rm -rfv $i; done