You will need to use fork
and exec
int fork_rv = fork();
if (fork_rv == 0)
{
// we're in the child
execl("/path/to/gedit", "gedit", 0);
// in case execl fails
_exit(1);
}
else if (fork_rv == -1)
{
// error could not fork
}
You will also need to reap your child so as not to leave a zombie process.
void reap_child(int sig)
{
int status;
waitpid(-1, &status, WNOHANG);
}
int main()
{
signal(SIGCHLD, reap_child);
...
}
In regards to zombie processes, you have a second option. It uses a bit more resources (this flavor forks twice), but the benefit is you can keep your wait closer to your fork which is nicer in terms of maintenance.
int fork_rv = fork();
if (fork_rv == 0)
{
fork_rv = fork();
if (fork_rv == 0)
{
// we're in the child
execl("/path/to/gedit", "gedit", 0);
// if execl fails
_exit(1);
}
else if (fork_rv == -1)
{
// fork fails
_exit(2);
}
_exit(0);
}
else if (fork_rv != -1)
{
// parent wait for the child (which will exit quickly)
int status;
waitpid(fork_rv, &status, 0);
}
else if (fork_rv == -1)
{
// error could not fork
}
What this last flavor does is create a child, which in turns creates a grandchild and the grandchild is what exec's your gedit program. The child itself exits and the parent process can reap it right away. So an extra fork but you keep all the code in one place.