There is no way to invoke
$parent->test = "hello world!";
$parent->child = new B();
and automatically have a reference to $parent in B.
Generally, there is four ways to structure your classes:
1. Aggregate the parent object via Injection, e.g.
class B{
protected $parent;
public function __construct($parent) {
$this->_parent = $parent;
}
public function setParent($parent) {
$this->_parent = $parent;
}
public function accessParent() {
$this->_parent->someMethodInParent();
}
}
Use constructor injection when the object has to have a parent when it's created. This is a has-a relationship and it creates a very loose coupling. There is no hardcoded dependencies in B, so you can easily swap out the Parent instance, for instance with a Mock when UnitTesting. Using Dependency Injection will make your code more maintainable.
In your UseCase, you'd pass $parent to B when creating B:
$parent->child = new B($parent);
2. Use Composition
class B{
protected $_parent;
public function __construct() {
$this->_parent = new Parent;
}
public function accessParent() {
$this->_parent->someMethodInParent();
}
}
This is also a has-a relationship, but couples the Parent class to B. It's also not an existing Parent instance, but a new instance. From the wording I find it somewhat odd to have a parent created by the child. Use this, when dependency is a class that is not considered to exist outside of the root class, but is part of the whole thing it represents.
For your UseCase, there is no way of doing $parent->child = new B();
and know what parent is when using this approach, unless $parent is a Singleton. If so, you could get the Singleton instance, e.g. Parent::getInstance() to achieve what you want, but note that Singletons are not everyone's favorite pattern, e.g. hard to test.
3. Use Inheritance
class B extends Parent {
public function __construct() {
parent::__construct();
}
public function accessParent() {
$this->someMethodInParent();
}
}
This way you create an is-a relationship. All public and protected methods and properties from the Parent class, (but not of a specific instance) will be available in B and you can access them via the $this
keyword of the B instance.
For your UseCase, this approach is not working, as you don't have to have an instance of Parent at all, but B would encapsulate everything of Parent when it's created
$b = new B;
4. Use global keyword
class B extends Parent {
protected $_parent;
public function __construct() {
global $parent;
$this->_parent = $parent;
}
public function accessParent() {
$this->_parent->someMethodInParent();
}
}
The global
keyword imports global variables into the current scope. In general, you should avoid using the global keyword in an OO context, but use one of the other three methods above, preferably the first one. While it's a language feature, it's frowned upon - although it is the next closest thing to the first one, e.g.
$parent->child = new B();
Anyway, hope that helps.