operator inside operator not working........

Question

char b;

operator<<(cout,(operator>>(cin,b)));

this is not compiling in vc++ because all 8 overloads cant convert this type.

can any one explain this.....

is their a problem with return type...........

Answer 1

The stream extraction operation i.e. op>> returns an object of type istream&. The op<< does not have an overload which takes istream& as its second parameter. You need to split the two actions or define one such overload.

Answer 2

char b; operator<<(cout,(operator>>(cin,b),b));

Answer 3

The problem is that the output operator that would work takes a void*, but that is a member. If you change it to the following, it will convert the istream& returned by the operator>> to void* and output it (and it is a null pointer if the extraction worked, and a non-NULL pointer otherwise):

cout.operator<<(operator>>(cin,b));

I'm not quite sure though why you are doing this. Can you please elaborate? If you want to output all stuff from cin right away, use the underlying buffer

cout << cin.rdbuf();