Your database is not in the first normal form. A non-normalized database will be very problematic to use and to query, as you are actually experiencing.
In general, you should be using at least the following structure. It can still be normalized further, but I hope this gets you going in the right direction:
CREATE TABLE users (
user_id int,
name varchar(100)
);
CREATE TABLE users_needs (
need varchar(100),
user_id int
);
Then you should store the data as follows:
-- TABLE: users
+---------+-------+
| user_id | name |
+---------+-------+
| 1 | joe |
| 2 | peter |
| 3 | steve |
| 4 | clint |
+---------+-------+
-- TABLE: users_needs
+---------+----------+
| need | user_id |
+---------+----------+
| housing | 1 |
| water | 1 |
| food | 1 |
| housing | 2 |
| rent | 2 |
| water | 2 |
| housing | 3 |
+---------+----------+
Note how the users_needs
table is defining the relationship between one user and one or many needs (or none at all, as for user number 4.)
To normalise your database further, you should also use another table called needs
, and as follows:
-- TABLE: needs
+---------+---------+
| need_id | name |
+---------+---------+
| 1 | housing |
| 2 | water |
| 3 | food |
| 4 | rent |
+---------+---------+
Then the users_needs
table should just refer to a candidate key of the needs
table instead of repeating the text.
-- TABLE: users_needs (instead of the previous one)
+---------+----------+
| need_id | user_id |
+---------+----------+
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 1 | 2 |
| 4 | 2 |
| 2 | 2 |
| 1 | 3 |
+---------+----------+
You may also be interested in checking out the following Wikipedia article for further reading about repeating values inside columns:
UPDATE:
To fully answer your question, if you follow the above guidelines, sorting, counting and aggregating the data should then become straight-forward.
To sort the result-set by needs, you would be able to do the following:
SELECT users.name, needs.name
FROM users
INNER JOIN needs ON (needs.user_id = users.user_id)
ORDER BY needs.name;
You would also be able to count how many needs each user has selected, for example:
SELECT users.name, COUNT(needs.need) as number_of_needs
FROM users
LEFT JOIN needs ON (needs.user_id = users.user_id)
GROUP BY users.user_id, users.name
ORDER BY number_of_needs;