I want to hold reference to object so it doesn't get deleted in bind function, but without using helper function.
struct Int
{
int *_int;
~Int(){ delete _int; }
};
void holdReference(boost::shared_ptr<Int>, int*) {} // helper
boost::shared_ptr<int> fun()
{
boost::shared_ptr<Int> a ( new Int );
// I get 'a' from some please else, and want to convert it
a->_int = new int;
return boost::shared<int>( a->_int, boost::bind(&holdReference, a, _1) );
}
Is there a way to declare holdReference function in place? Like with lambda expressions or sth? (without using this nasty holdReference function, that have to be declared outside the scope of fun function) I had few tries but non of them compiled :)
Ok, here is more detailed example:
#include <boost/shared_ptr.hpp>
#include <boost/bind.hpp>
// the case looks more or less like this
// this class is in some dll an I don't want to use this class all over my project
// and also avoid coppying the buffer
class String_that_I_dont_have
{
char * _data; // this is initialized in 3rd party, and released by their shared pointer
public:
char * data() { return _data; }
};
// this function I created just to hold reference to String_that_I_dont_have class
// so it doesn't get deleted, I want to get rid of this
void holdReferenceTo3rdPartyStringSharedPtr( boost::shared_ptr<String_that_I_dont_have>, char *) {}
// so I want to use shared pointer to char which I use quite often
boost::shared_ptr<char> convert_function( boost::shared_ptr<String_that_I_dont_have> other)
// 3rd party is using their own shared pointers,
// not the boost's ones, but for the sake of the example ...
{
return boost::shared_ptr<char>(
other->data(),
boost::bind(
/* some in place here instead of holdReference... */
&holdReferenceTo3rdPartyStringSharedPtr ,
other,
_1
)
);
}
int main(int, char*[]) { /* it compiles now */ }
// I'm just looking for more elegant solution, for declaring the function in place