Virtual function

Question

class a
{
 virtual void foo(void) ;
};

class b : public  a
{
public:
 virtual void foo(void)
  {
  cout<< "class b";
  }
};

int main ( ) 
{
class a *b_ptr = new b ;
b_ptr->foo();
}

please guide me why the b_ptr->foo() will not call the foo() function of the class b?

Answer 1

Make that

class a
{
public:
    virtual void foo(void);
};

You can't override a private function. Though I'm not sure how you managed to call b_ptr->foo() anyways since a::foo is private.

Answer 2

As you've written the code, it won't compile due to access control violations. Since b_ptr is actually of type a * and a::foo is private, the compiler won't allow that.

But make a::foo public and that will correctly call b::foo.

There is also the problem that you have not defined a::foo so your program won't link. You need to either define it or make it pure virtual (i.e virtual void foo(void) = 0;).

Answer 3

Because a:foo() is not public.