C++ print value of a pointer

Question

I have an array of double pointers, but every time I try do print one of the values the address gets printed. How do I print the actual value?

cout << arr[i] ? cout << &arr[i] ? they both print the address

Does anyone know?

Answer 1

If it's really an array of (initialized) double pointers, i.e.:

double *arr[] = ...
// Initialize individual values

all you need is:

cout << *arr[i];

Answer 2

cout << *(arr[i]) will print the value.

Answer 3

If "arr" is declared as

double* arr[..];

Then you would use:

cout << *(arr[i])

Answer 4

cout << *(arr[i]);