Generate a few models from existing database in Django

Question

I know this exists

django-admin.py inspectdb > models.py

However, is there an easy way to limit it? Without manually deleting what I don't want.

I'm connecting to a database that has over one hundred tables, but I only want models of about 4 or 5. Is there an easy way to generate models from a few given tables?

They are quite big tables, so I don't fancy typing them all out either.

Answer 1

donot use syncdb > models.py ,it not a good practice.Make ur models manually and add managed=False to it.if u will not add it ur all db tables can be deleted via sinfle command.After creating ur models then run the syncb so that tables are linked

Answer 2

I just did this myself, also with Oracle. It's possible - but not pretty.

Assuming you know the names of the tables you want -

open django/db/backends/oracle/introspection.py. There is a function get_table_list:

def get_table_list(self, cursor):
    "Returns a list of table names in the current database."
    cursor.execute("SELECT TABLE_NAME FROM USER_TABLES")
    return [row[0].lower() for row in cursor.fetchall()]

Just replace it with something like

def get_table_list(self, cursor):
    names = ['mytable1', 'mytable2', 'mytable3']
    return names

Then run your inspectdb and it will be a lot more managable :)