Function overloading

Question

I found this code , and i m not sure that whether overloading should happen or not.

void print( int (*arr)[6], int size );

void print( int (*arr)[5], int size );

what happens if I pass pointer to an array of 4 elements , to it should come...

any thread will be helpful.

Answer 1

KennyTM's answer is the correct one. Here's an additional thought, though, based on the fact that your question comes with a C++ tag. In C++, you can use templates with non-type arguments to find out array dimensions:

#include <iostream>

template< std::size_t N >
void print(int (&arr)[N]) {std::cout << N << '\n';}

int main()
{
    int arr[6];
    print(arr);
    return 0;
}

Answer 2

The call would be ambiguous as none of the two overloads would be able to convert to int (*arr)[4]. You need to pass in an element of 5 or 6 elements explicitly.

VS2008 gives:

error C2665: 'print' : none of the 2 overloads could convert all the argument types
(2088): could be 'void print(int (*)[5],int)'
(2093): or       'void print(int (*)[6],int)'
 while trying to match the argument list '(int (*)[4], int)'

Hope that helps.