Python: load variables in a dict into namespace

Question

I want to use a bunch of local variables defined in a function, outside of the function. So I am passing x=locals() in the return value.

How can I load all the variables defined in that dictionary into the namespace outside the function, so that instead of accessing the value using x['variable'], I could simply use variable.

Answer 1

Don't do that. Just don't. Seriously.

Answer 2

Consider the Bunch alternative:

class Bunch(object):
  def __init__(self, adict):
    self.__dict__.update(adict)

so if you have a dictionary d and want to access (read) its values with the syntax x.foo instead of the clumsier d['foo'], just do

x = Bunch(d)

this works both inside and outside functions -- and it's enormously cleaner and safer than injecting d into globals()! Remember the last line from the Zen of Python...:

>>> import this
The Zen of Python, by Tim Peters
   ...
Namespaces are one honking great idea -- let's do more of those!

Answer 3

This is perfectly valid case to import variables in
one local space into another local space as long as
one is aware of what he/she is doing.
I have seen such code many times being used in useful ways.
Just need to be careful not to pollute common global space.

You can do the following:

adict = { 'x' : 'I am x', 'y' : ' I am y' }

locals().update(adict)

blah(x)

blah(y)