tags:

views:

103

answers:

1

I have 3 tables:

users:

Id   Login
1    John
2    Bill
3    Jim

computers:

Id   Name
1    Computer1
2    Computer2
3    Computer3
4    Computer4
5    Computer5

sessions:

UserId   ComputerId   Minutes
1        2            47
2        1            32
1        4            15
2        5            5
1        2            7
1        1            40
2        5            31

I would like to display this resulting table:

Login   Total_sess   Total_min   Most_freq_computer   Sess_on_most_freq   Min_on_most_freq
John    4            109         Computer2            2                   54
Bill    3            68          Computer5            2                   36
Jim     -            -           -                    -                   -

Myself I can only cover first 3 columns with:

SELECT Login, COUNT(sessions.UserId), SUM(Minutes) FROM users
LEFT JOIN sessions
ON users.Id = sessions.UserId GROUP BY users.Id

And some kind of other columns with:

SELECT main.*
FROM (SELECT UserId, ComputerId, COUNT(*) AS cnt ,SUM(Minutes)
FROM sessions
GROUP BY UserId, ComputerId) AS main
INNER JOIN (
SELECT ComputerId, MAX(cnt) AS maxCnt FROM (
SELECT ComputerId, UserId, COUNT(*) AS cnt FROM sessions GROUP BY ComputerId, UserId
)
AS Counts GROUP BY ComputerId) 
                    AS maxes
ON main.ComputerId = maxes.ComputerId
AND main.cnt = maxes.maxCnt

But I need to get whole resulting table in one query. I feel I'm doing something completely wrong. Need help.

+3  A: 

Here you are:

SELECT    u.login, t1.total_sess, t1.total_min, t2.mf, t2.sess_mf, t2.min_mf
FROM      users u
LEFT JOIN (
  SELECT   userid, COUNT(minutes) AS total_sess, SUM(minutes) AS total_min
  FROM     sessions
  GROUP BY userid
) AS t1 ON t1.userid = u.id
LEFT JOIN (
  SELECT   userid, name AS mf, COUNT(*) AS sess_mf, SUM(minutes) AS min_mf
  FROM     sessions s
  JOIN     computers c ON c.id = s.computerid
  GROUP BY userid, computerid
  HAVING   COUNT(computerid) >= ALL(SELECT   COUNT(*)
                                    FROM     sessions s2
                                    WHERE    s2.userid = s.userid
                                    GROUP BY s2.computerid)
) AS t2 ON t2.userid = u.id

I'm using MySQL syntax, but it should be pretty portable.

If you need anything more, feel free to ask!

EDIT: I updated the query, the previous one was wrong :(

Yassin
@Yassin: There's still a problem with your `HAVING` clause. At the moment it works because both users had a `Sess_on_most_freq` of 2, but if you add another session for Bill on Computer 5, the query would break. Adding `WHERE user_id = s.user_id` in the HAVING clause should fix it.
Daniel Vassallo
Thanks! You are awesome! I would appreciate if you recommend me some goob books on SQL.
+1 for approach
Unreason
@Daniel: You're right. I updated the query. +1
Yassin
@Daniel, good catch, also in that case GROUP BY userid is redundant.
Unreason
@trixet: Learning SQL (ISBN 0596007272) and SQL In A Nutshell, 2nd Edition (ISBN 0596004818)
Yassin