Modifying multiplying calculation to use delta time

Question

function(deltaTime) {
  x = x * FACTOR; // FACTOR = 0.9
}

This function is called in a game loop. First assume that it's running at a constant 30 FPS, so deltaTime is always 1/30.

Now the game is changed so deltaTime isn't always 1/30 but becomes variable. How can I incorporate deltaTime in the calculation of x to keep the "effect per second" the same?

---

And what about

function(deltaTime) {
  x += (target - x) * FACTOR; // FACTOR = 0.2
}

Answer 1

x = x * Math.pow(0.9, deltaTime*30)

Edit

For your new update:

x = (x-target) * Math.pow(1-FACTOR, deltaTime*30) + target;

To show how I got there:

Let x0 be the initial value, and xn be the value after n/30 seconds. Also let T=target, F=factor. Then:

x1 = x0 + (T-x0)F = (1-F)x0 + TF
x2 = (1-F)x1 + TF = (1-F)^2 * x0 + (1-F)TF + TF

Continuing with x3,x4,... will show:

xn = (1-F)^n * x0 + TF * (1 + (1-F) + (1-F)^2 + ... + (1-F)^(n-1))

Now substituting the forumla for sum of a geometric sequence will give the result above. This really only proves the result for integer n, but it should work for all values.

Answer 2

x = x * powf(0.9, deltaTime / (1.0f / 30.0f))