The convolution of h and x (h*x) will be something like h*x = SUM h[n-q]*x[n], where the sum is performed over all possible q's depending on the size of h. If h and x are infinite then the sum goes from -INF to +INF.
Convolution is an operation distinct from multiplication. If h[n] = delta[n-a] represents an impulse at n=a, then the convolution of h and any function f[n] is equal to conv(h,f) = f[n-a], and you should be able to determine the answer to your question through superposition, since convolution and addition are both linear operators.
In this case, (and more so if you are unsure about convolution), it is convenient to do the convolution graphically, to grap the basics and relate that to the analytical formula.