how to make a name from random numbers?

Question

my program makes a random name that could have a-z this code makes a 16 char name but :( my code wont make the name and idk why :( can anyone show me what's wrong with this?

char name[16];
void make_random_name()
{

  byte loop = -1;

  for(;;)
  {
      loop++;

      srand((unsigned)time(0));
      int random_integer;

      random_integer = (rand()%10)+1;

      switch(random_integer)
      {
      case '1': name[loop] = 'A';
          break;
      case '2': name[loop] = 'B';
          break;
      case '3': name[loop] = 'C';
          break;
      case '4': name[loop] = 'D';
          break;
      case '5': name[loop] = 'E';
          break;
      case '6': name[loop] = 'F';
          break;
      case '7': name[loop] = 'G';
          break;
      case '8': name[loop] = 'Z';
          break;
      case '9': name[loop] = 'H';
          break;
      }

      cout << name << "\n";

      if(loop > 15)
      {
          break;
      }

  }


 }

Answer 1

random_integer is an integer, you are comparing it to a bunch of characters from the ASCII character set - '1' as a character literal is actually 49 in decimal. As 49 is not in the range of your random numbers, it'll never get hit.

Try changing your case statements to

case 1: ...

instead of

case '1': ...

Answer 2

srand((unsigned)time(0));

Take this out of the for loop, you need to seed it once only.

case '1':

1 does not mean integer 1, rather it is character 1 which translates (ascii) to integer 49. Change it to -

case 1 :

Answer 3

Or just use

char name[16];
for (i = 0; i < sizeof name; ++i) {
  name[i] = "ABCDEFGHIJ"[rand() % 10];
}

Answer 4

There are so many things wrong with this that I'll list them:

1) You don't null terminate the string. 2) You're needlessly using a switch statement for data that could very very easily be done with array indexing. 3) You're calling srand in a loop. 4) for(;;) { i++ ... -- Really? 5) Don't bring your homework to stack overflow. No professional developer would ever post that (or if they did, I fear for their employer).