Just like the title says, wanted for testing purposes.
Thanks!
That won't always generate a valid address. (On rare occasions, it could generate `0.0.0.0` or `255.255.255.255` which are not valid addresses)
webdestroya
2010-05-11 04:35:02
Do those two addresses break some rule? They look OK to me. Since the OP only asked a vague question, those two are just as good as any other.
dbasnett
2010-05-11 12:55:11
If I remember right, they are good IP numbers but are pre-assigned to network broadcasts. No machine can have an IP of 0.0.0.0 or 255.255.255.255, but they can respond to requests to those numbers. If that makes sense in an application then it's OK to use them. See http://en.wikipedia.org/wiki/Broadcast_address for more info.
Greg
2010-05-11 18:33:28
+5
A:
If you want a truly random IP address, Array.new(4){rand(256)}.join('.') does it
Chubas
2010-05-11 04:31:40
+2
A:
I've used this before to generate a random ip then validate it with Resolv
ip = "#{rand(99)}.#{rand(100)}.#{rand(10)}.#{rand(255)}"
begin
if ip
host = Resolv.new.getname(ip)
puts "#{c} #{real_ip.length} #{ip} #{host}"
end
rescue Exception => e
puts "FAKE #{ip}"
end
jspooner
2010-05-11 04:55:28
+5
A:
You could use IPAddr
require 'ipaddr'
ipv4 = IPAddr.new(rand(2**32),Socket::AF_INET)
ipv6 = IPAddr.new(rand(2**128),Socket::AF_INET6)
Aaron Lee
2010-05-11 14:04:37