Class inheriting from several Interfaces having same method signature

Question

Say, I have three interfaces:

public interface I1
{
    void XYZ();
}
public interface I2
{
    void XYZ();
}
public interface I3
{
    void XYZ();
}

A class inheriting from these three interfaces:

class ABC: I1,I2, I3
{
      // method definitions
}

Questions:

• If I implement like this:

  class ABC: I1,I2, I3 {

      public void XYZ()
      {
          MessageBox.Show("WOW");
      }
  

  }

It compiles well and runs well too! Does it mean this single method implementation is sufficient for inheriting all the three Interfaces?

• How can I implement the method of all the three interfaces and CALL THEM? Something Like this:

  ABC abc = new ABC();
  abc.XYZ(); // for I1 ?
  abc.XYZ(); // for I2 ?
  abc.XYZ(); // for I3 ?
  

I know it can done using explicit implementation but I'm not able to call them. :(

Answer 1

You can call it. You just have to use a reference with the interface type:

I1 abc = new ABC();
abc.XYZ();

If you have:

ABC abc = new ABC();

you can do:

I1 abcI1 = abc;
abcI1.XYZ();

or:

((I1)abc).XYZ();

Answer 2

If you use explicit implementation, then you have to cast the object to the interface whose method you want to call:

class ABC: I1,I2, I3
{
    void I1.XYZ() { /* .... */ }
    void I2.XYZ() { /* .... */ }
    void I3.XYZ() { /* .... */ }
}

ABC abc = new ABC();
((I1) abc).XYZ(); // calls the I1 version
((I2) abc).XYZ(); // calls the I2 version