If it would be 6^x = 1 or 6^x = 6 or 6^x = 36 it would be extremely easy, but how to solve this equation:
6^x = 5
I don't need an answer, I want to find out how to solve equations like this one, I need solution.
Thanks.
views:
204answers:
4
A:
Solve[6^x == 5, x]
See Wolfram Alpha do this here: http://www.wolframalpha.com/input/?i=Solve[6^x+%3D%3D+5,+x]
Also take a look at http://reference.wolfram.com/mathematica/tutorial/SolvingEquations.html
Christian Jonassen
2010-05-24 07:50:38
+10
A:
Take logs of both sides:
log(6^x) = log(5)
Simplify using standard log rules:
x log(6) = log(5)
Divide:
x = log(5) / log(6)
Doesn't matter what base you take.
David M
2010-05-24 07:50:43
Omg, so easy and I didn't manage to do it on exam... Thank you anyways.
hey
2010-05-24 07:54:03
Actually the x such that b^x = a is the definition of log_b(a).
starblue
2010-05-24 14:58:04
Absolutely right. And hence the formula normally given for log_b(a).
David M
2010-05-24 15:35:38