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5

Possible Duplicate:
What does *args and **kwargs mean?

What does the * operator mean in Python, such as in code like zip(*x) or f(**k)?

  1. How does it work internally in the interpretor?
  2. Is it fast or not?
  3. When is it useful and when is it not?
  4. Should it be used in a function declaration or in a call?
+1  A: 

In a function call the single star turns a list into seperate arguments (e.g. zip(*x) is the same as zip(x1,x2,x3) if x=[x1,x2,x3]) and the double star turns a dictionary into seperate keyword arguments (e.g. f(**k) is the same as f(x=my_x, y=my_y) if k = {'x':my_x, 'y':my_y}.

In a function definition it's the other way around: the single star turns an arbitrary number of arguments into a list, and the double start turns an arbitrary number of keyword arguments into a dictionary. E.g. def foo(*x) means "foo takes an arbitrary number of arguments and they will be accessible through the list x (i.e. if the user calls foo(1,2,3), x will be [1,2,3])" and def bar(**k) means "bar takes an arbitrary number of keyword arguments and they will be accessible through the dictionary k (i.e. if the user calls bar(x=42, y=23), k will be {'x': 42, 'y': 23})".

sepp2k
+3  A: 

It is called the extended call syntax. From the documentation:

If the syntax *expression appears in the function call, expression must evaluate to a sequence. Elements from this sequence are treated as if they were additional positional arguments; if there are positional arguments x1,..., xN, and expression evaluates to a sequence y1, ..., yM, this is equivalent to a call with M+N positional arguments x1, ..., xN, y1, ..., yM.

and:

If the syntax **expression appears in the function call, expression must evaluate to a mapping, the contents of which are treated as additional keyword arguments. In the case of a keyword appearing in both expression and as an explicit keyword argument, a TypeError exception is raised.

Mark Byers
Just adding a footnote to the textbook answer - before syntactical support arrived, the same functionality was achieved with the built-in `apply()` function
Jeremy Brown
+22  A: 

The single star * unpacks the sequence/collection into positional arguments, so you can do this:

def sum(a, b):
    return a + b

values = (1, 2)

s = sum(*values)

This will unpack the tuple so that it actually executes as:

s = sum(1, 2)

The double star ** does the same, only using a dictionary and thus named arguments:

values = { 'a': 1, 'b': 2 }
s = sum(**values)

You can also combine:

def sum(a, b, c, d):
    return a + b + c + d

values1 = (1, 2)
values2 = { 'c': 10, 'd': 15 }
s = sum(*values1, **values2)

will execute as:

s = sum(1, 2, 10, 15)

Also see section 4.7.4 - Unpacking Argument Lists of the Python documentation.


Additionally you can define functions to take *x and **y arguments, this allows a function to accept any number of positional and/or named arguments that aren't specifically named in the declaration.

Example:

def sum(*values):
    s = 0
    for v in values:
        s = s + v
    return s

s = sum(1, 2, 3, 4, 5)

or with **:

def get_a(**values):
    return values['a']

s = get_a(a=1, b=2)      # returns 1

this can allow you to specify a large number of optional parameters without having to declare them.

And again, you can combine:

def sum(*values, **options):
    s = 0
    for i in values:
        s = s + i
    if "neg" in options:
        s = -s
    return s

s = sum(1, 2, 3, 4, 5)            # returns 15
s = sum(1, 2, 3, 4, 5, neg=True)  # returns -15
Lasse V. Karlsen
Thanks, very helpful!
psihodelia
why would you need this, couldn't the function just iterate over the supplied list without it being expanded?
Martin Beckett
Sure, but then you would have to call it: `s = sum((1, 2, 3, 4, 5))` or `s = sum([1, 2, 3, 4, 5])`, the `*values` option makes the call look like it takes a number of arguments, but they're packed up into a collection for the function code.
Lasse V. Karlsen
+4  A: 

One small point: these are not operators. Operators are used in expressions to create new values from existing values (1+2 becomes 3, for example. The * and ** here are part of the syntax of function declarations and calls.

Ned Batchelder
+1  A: 

I find this particularly useful for when you want to 'store' a function call.

For example, suppose I have some unit tests for a function 'add':

def add(a, b): return a + b
tests = { (1,4):5, (0, 0):0, (-1, 3):3 }
for test, result in tests.items():
   print 'test: adding', test, '==', result, '---', add(*test) == result

There is no other way to call add, other than manually doing something like add(test[0], test[1]), which is ugly. Also, if there are a variable number of variables, the code could get pretty ugly with all the if-statements you would need.

Another place this is useful is for defining Factory objects (objects that create objects for you). Suppose you have some class Factory, that makes Car objects and returns them. You could make it so that myFactory.make_car('red', 'bmw', '335ix') creates Car('red', 'bmw', '335ix'), then returns it.

def make_car(*args):
   return Car(*args)

This is also useful when you want to call a superclass' constructor.

orangeoctopus
I like your examples. But, I think -1 + 3 == 2.
eksortso
I intentionally put something in there that would fail :)
orangeoctopus