Is it possible to have a function pointer to a template function in c++?

Question

I want to know if it's possible to create a template function and then create a function pointer that points to that template function. Is this possible?

I'm using VS2008.

The following code gets this compile time error:

"cannot convert from 'overloaded-function' to 'int (__cdecl *)(int &,int &)' None of the functions with this name in scope match the target type"

template<typename T>
T tfunc(const T &x, const T &y){
    return (x < y ? x : y);
}

int (*tfunc_ptr)(int &, int &) = &tfunc<int>;

Answer 1

Your arguments are wrong. tfunc takes is arguments by const references so your function pointer must do the same;

int (*tfunc_ptr)(const int &, const int &) = &tfunc<int>;

Answer 2

Hmm...what happened to the answer you had? It was correct. You need to provide the template parameter:

int (*tfunc_ptr)(int const&,int const&) = &tfunc<int>;

Oh, and note the references. Your template has them, your funptr does not. That needs to match.

Answer 3

template<typename T>
T tfunc(const T &x, const T &y){
 return (x < y ? x : y);
}

int (*tfunc_ptr)(const int&, const int&) = tfunc<int>;

int main() {
    int b = tfunc_ptr( 1, 2 );
}