Hi,
I am still a beginner with XSLT but I am having a difficult task in hand.
I have a non-xml file which needs to be transformed. The format of the file is a s follows:
type1
type1line1
type1line2
type1line3
type2
type2line1
type2line2
type3
type3line1
type3line2
types (type1, type2, ...
) are specified using certain codes which don't have a specific order. Each type has multiple line
underneath.
So, I need to transform this file but the problem is that for each type
I have to do a different transformation for each of it's underlying lines.
Now, I can read the string line by line and determine that a new type has begun but I don't know how to set a flag (indicating the type) to use it in the underlying lines.
Here is what I have right now:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:param name="testString" as="xs:string">
type1
line1
line2
type1
line1
</xsl:param>
<xsl:template match="/">
<xsl:call-template name="main">
<xsl:with-param name="testString" select="$testString"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="main">
<xsl:param name="testString"/>
<xsl:variable name="iniFile" select="$testString"/>
<config>
<xsl:analyze-string select="$iniFile" regex="\n">
<xsl:non-matching-substring>
<item>
<xsl:choose>
<xsl:when test="starts-with(., 'type1')">
<!-- do a specific transformation-->
</xsl:when>
<xsl:when test="starts-with(., 'type2')">
<!-- do another transformation-->
</xsl:when>
</xsl:choose>
</item>
</xsl:non-matching-substring>
</xsl:analyze-string>
</config>
</xsl:template>
</xsl:stylesheet>
Any idea about how to solve the problem.