I have a list of dictionaries that looks like this:
[{'id':1,'name':'Foo'},{'id':2,'name':'Bar'}]
I'd like to convert the values from each dict into a list of tuples like this:
[(1,'Foo'),(2,'Bar')]
How can I do this?
views:
77answers:
2
+7
A:
>>> l = [{'id':1,'name':'Foo'},{'id':2,'name':'Bar'}]
>>> [tuple(d.values()) for d in l]
[(1, 'Foo'), (2, 'Bar')]
SilentGhost
2010-07-08 09:13:53
simple and exactly what it says on the tin, thanks very much
chrism
2010-07-08 09:17:45
and probably wrong. see answer below.
Marco Mariani
2010-07-08 09:45:31
@Marco: it gives consistent order for given keys, there is nothing wrong about this answer.
SilentGhost
2010-07-08 10:54:32
You can't guarantee `id` will always come out before `name`, especially across different versions/implementations. For example entering the above example in IronPython (eg. trypython.org) currently gives `[('Foo', 1), ('Bar', 2)]`. You can't even be sure that two dicts with the same keys will give their `keys()` in the same order (they will for simple cases like this, but that's an implementation detail you're not supposed to rely on).
bobince
2010-07-08 11:22:53
+5
A:
Note that the approach in SilentGhost's answer doesn't guarantee the order of each tuple, since dictionaries and their values() have no inherent order. So you might just as well get ('Foo', 1) as (1, 'Foo'), in the general case.
If that's not acceptable and you definitely need the id first, you'll have to do that explicitly:
[(d['id'], d['name']) for d in l]
bobince
2010-07-08 09:38:09