How to truncate string in groovy
I used :
def c = truncate("abscd adfa dasfds ghisgirs fsdfgf", 10)
but getting error .
thanks in advance .
views:
43answers:
1
+4
A:
In Groovy, strings can be considered as ranges of characters. As a consequence, you can simply use range indexing features of Groovy and do myString[startIndex..endIndex].
As an example,
"012345678901234567890123456789"[0..10]
outputs
"0123456789"
Riduidel
2010-07-12 07:36:03
In addition ranges can also be negative with `-1` that means the last character of the string. So whenever you will need to truncate to the last part of a string you can easily do `string[-11..-1]`
Jack
2010-07-12 10:59:14
@Riduidel, this is not working when given "012345"[0..20]. I get the results in loop and some will have more and some dont have more characters. It should apply for the string which exceeds 20 chars. thanks
Srinath
2010-07-12 13:43:37
In your loop you would need to ensure you only substring if the string is greater than 10, for example, def s = it.size() > 10 ? it[0..10] : it
John Wagenleitner
2010-07-12 14:38:02
@john, yeah meanwhile i applied the same logic and works. thanks
Srinath
2010-07-12 14:40:26