How to encode # character in the url + php + Joomla

Question

I am trying to fetch a variable address from my current URL using JRequest::getVar('address') method. But if the address value has a (#) character, the part after the # character is not retrieved.

I understand that URI is a combination of query + fragment and the part after a hash symbol is treated as a fragment. I have tried to use urlencode method but it still doesn't solve the problem.

Can anyone please tell me how to solve the issue?

Answer 1

I guess you will have to replace the hash-symbol on your own. For example:

str_replace($the_url, '#', '-');

I don't know, where exactly you have to do that, because I don't know how the Joomla!-Framework handles links and urls. But I am sure, that someone else can help here any further...

Answer 2

What is the problem with using urlencode? It should replace # with %23 and all should be well. You can try JRequest::getVar(str_replace('#', '%23', 'address')) which should do the trick. Can you post an example URL that doesn't get properly urlencoded?

Answer 3

The part after # is never sent to Apache/PHP, and can therefore not be retrieved by a PHP script. What you need to do, is to url encode the ADDRESS parameter of the URL.

test.com/index.php?ADDRESS=<?= urlencode('101 Street #6 City') ?>

That code will generate the following url

test.com/index.php?ADDRESS=101+Street+%236+City

Now on this URL, you can retrieve address with JRequest::getVar('ADDRESS')

Answer 4

Check this Joomla doc out. You can retrieve what Joomla call the 'fragment' by doing:

$uri = 'http://fredbloggs:[email protected]:8080/path/to/Joomla/index.php?task=view&id=32#anchorthis';
$u =& JURI::getInstance( $uri );
echo 'Fragment is ' . $u->getFragment();