How to replace allocators of stl with actual source code

Question

Hello,

I need to replace allocators with their original source code. I am extracting exported methods from PE export table and facing strange lengthy allocators where STL containers were used in original source code . for example if source code was

   typedef std::list<std::basic_string<_TCHAR> > TokenList;
   EXPORTS_API const TokenList& getLiteralList( );

from export table i am getting

std::list<class std::basic_string<unsigned short, std::char_traits<unsigned short>,class
 std::allocator<unsigned short> >,class std::allocator<class std::basic_string<unsigned 
short,struct std::char_traits<unsigned short>,class std::allocator<unsigned short> > > > 
const & __thiscall CExpressionTokenizer::getLiteralList(void)

That's annoying. How to get backtrack from above strange lengthy allocators to original source code, more over when comes typedefs it increases in size more and more.

Regards Usman

Answer 1

I think you mean that you want to be able to determine a more succinct type name from the export table. The standard allocator (std::allocator) is the default template parameter for allocator parameter in most standard container class templates so you can just remove the entire allocator parameter from the template specialization to come up with a simpler expression of the same type.

E.g.

std::list<class std::basic_string<unsigned short, std::char_traits<unsigned short>,class
std::allocator<unsigned short> >,class std::allocator<class std::basic_string<unsigned 
short,struct std::char_traits<unsigned short>,class std::allocator<unsigned short> > > > 
const & __thiscall CExpressionTokenizer::getLiteralList(void)

becomes

std::list<class std::basic_string<unsigned short, std::char_traits<unsigned short> > > 
const & __thiscall CExpressionTokenizer::getLiteralList(void)

Answer 2

I believe you are talking about decoding the error messages? Try STLFilt.