I would like to do the equivalent off this (ruby code) in python for a Django project I am working on. I want to make a filmstrip image of X number of images in a folder.
+3
A:
Do you mnean something like this? Use PIL to make a "contact sheet" of images?
Perhaps there are others here that are closer to what you want: http://code.activestate.com/recipes/tags/graphics/
S.Lott
2008-12-02 18:03:27
It's something like this, but this is over complicated, i want a singlecolumn "list" of images, and need the images to be loaded from a folder. I guess it is possible to modify that script to do that.
Espen Christensen
2008-12-02 19:26:51
My thought is that the row number is always 0. Based on that, you can simplify this considerably.
S.Lott
2008-12-02 19:39:28
+1
A:
Here is a function that wraps the contact sheet function S.Lott mentioned.
#!/usr/bin/env python
import os, os.path
from contactsheet import make_contact_sheet
def make_film_strip(fnames,
(photow,photoh),
(marl,mart,marr,marb),
padding):
return make_contact_sheet(fnames,
(1, len(fnames)),
(photow,photoh),
(marl,mart,marr,marb),
padding)
It is assuming the recipe is saved as contactsheet.py
. Usage is:
fstrip = filmstrip.make_film_strip(filmstrip.fnames, (120, 120), (0,0,0,0), 0)
fstrip.save('/path/to/file.format')
Tested.
muhuk
2008-12-02 20:29:31
Thanks, the wrapping is good, thanks but i think i will try to make å decoupled solution, just modify the script and see if i can make it work...
Espen Christensen
2008-12-02 23:40:49