I can make a call from my app by use this APIs.
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:XXXXXX"]];
I would like to return to my app where I left after the users ends the call. Is that possible?
I can make a call from my app by use this APIs.
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:XXXXXX"]];
I would like to return to my app where I left after the users ends the call. Is that possible?
Try this:
UIWebView *callingWebview;
[callingWebview loadRequest:[NSURLRequest requestWithURL:]];
Hawsky when I try with this,A alert is dispalyed to trigger call or not ,requesting user.I want to trigger call with out the user input.How to do...