Leveraging sum()
should get better performance when adding more than a few dicts
>>> dict1 = [{'a':2, 'b':3},{'a':3, 'b':4}]
>>> from operator import itemgetter
>>> {k:sum(map(itemgetter(k), dict1)) for k in dict1[0]} # Python2.7+
{'a': 5, 'b': 7}
>>> dict((k,sum(map(itemgetter(k), dict1))) for k in dict1[0]) # Python2.6
{'a': 5, 'b': 7}
adding Stephan's suggestion
>>> {k: sum(d[k] for d in dict1) for k in dict1[0]} # Python2.7+
{'a': 5, 'b': 7}
>>> dict((k, sum(d[k] for d in dict1)) for k in dict1[0]) # Python2.6
{'a': 5, 'b': 7}
I think Stephan's version of the Python2.7 code reads really nicely