Hi
I have found out that you can't open(filepath) when filepath length is bigger that 255 even if the filename itself is 10 characters long( the remaining part is the directory path).
Any idea to work around this issue? (python 2.6 on win32)
Hi
I have found out that you can't open(filepath) when filepath length is bigger that 255 even if the filename itself is 10 characters long( the remaining part is the directory path).
Any idea to work around this issue? (python 2.6 on win32)
A Windows OS level solution is to use the DOS SUBST command to define a pseudo drive at a particular directory.
SUBST Q: C:\really\long\path\name\full\of\sub\directories
Then you can access the files in that directory as Q:filename
.