Class name macro

Question

Possible Duplicate:
CLASS macro in C++

Hello, are there any ways to get name of class with macro like _FUNCTION_ for function name? The only ideas I have is inheriting some base class with pure virtual toString and define the names by hands eash time. Thanks.

Answer 1

Use a macro to define the class:

#define CLASS_WITH_NAME(name)  name { const char * __NAME = #name;

class CLASS_WITH_NAME(class_name) // No "{" here!

Ugly hack but the best I can think of.

Answer 2

Easiest is probably (to define a macro) calling some function to derive the class name from __FUNCTION__ (or __PRETTY_FUNCTION__ for GCC, or maybe even __FILE__).

Answer 3

It depends what exactly is the context. A rough equivalent to get the implementation defined internal name of the class could be to use typeid operator as shown. Note that the output is implementation defined.

typeid(yourclass).name()

Answer 4

Another alternate could be as follows, though it has it's own downside

map<string, string> classdescrmap;     // store association system name, development name

struct A{
    A(){
        classdescrmap[typeid(*this).name()] = "A";
    }
};

struct B : A{
    B(){
        classdescrmap[typeid(*this).name()] = "B";
    }
};

string getname(string const &key){
    return classdescrmap[key];
}

int main(){
    B b;
    cout << getname(typeid(b).name());
}